Respuesta :
Answer:
111.1 meters flown from bat
Explanation:
So one bike is going at 8m/s and the other bike is going at 10m/s in the direction towards the other bike. So we can make one bikes velocity =0 and the other we add the velocities together to get V of bike a = 18m/s while velocity of bike b =0m/s. Then we use the distance apart to find the time. so we take our average velocity formula and rearrange it to time = displacement/average velocity. This gives t = 100/18=5.55secs. We then take the bats velocity to find to the distance traveled. 5.55secs = x/20m/s. We just cross multiply to get 111.1 repeating which we just say is 111.1m traveled from the bat.
The distance traveled by the bat before the two bikes meet is 1,000 m.
Time taken for for the two bikes to be in the same place
The time taken for the bikes to meet or intersect each other is calculated as follows;
(Va - Vb)t = d
where;
- t is the time taken for the bikes to meet each other
- d is the distance between the bikes
- Va is the velocity of the first bike
- Vb is the velocity of the second bike
(10 m/s - 8 m/s)t = 100 m
2 m/s (t) = 100 m
t = 100 m / 2 m/s
t = 50 seconds
Distance traveled by the bat within this period
Distance = average speed x time
Distance = 20 m/s x 50 s
Distance = 1,000 m
Thus, the distance traveled by the bat before the two bikes meet is 1,000 m.
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