Objects 1 and 2 attract each other with an electrostatic force of 72.0 units. if the charge of object 1 is halved, then the electrostatic force is 36.0 units
Let's understand the answer
The electrostatic force is the force that exists between two charged particles which is given by:
[tex]F = K\frac{Q_{1}Q_{2}}{r^{2}}[/tex]
where
k is the Coulomb's constant
q1 and q2 are the two charges
r is the distance between the charges
In this problem, the charge of object 2 is doubled, so
[tex]F = K\frac{\frac{Q_{1}}{2} Q_{2}}{r^{2}}[/tex]
[tex]F = \frac{K}{2} \frac{Q_{1} Q_{2}}{r^{2}}[/tex]
[tex]F = \frac{F_{initial}}{2}[/tex]
So, the electrostatic force will be halved.
Since as the initial electrostatic force is
F = 72.0 units
the new force will be
72/2 = 36 units
Learn more about electrostatic force here
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