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What volume of h2 gas will be generated in reaction 2 described in the passage if 10.00 l of a 5.00 m solution of k2mno4 react at standard temperature and pressure (stp)?

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jaquelinefvr

The chemical reaction related to the question will be as follows:

  • [tex]2K_{2}MNO_{4} + 2H_{2}O[/tex] ⇒ [tex]2KMNO_{4} + 2KOH + H_{2}[/tex]

How to calculate the volume of gas for this reaction?

It is necessary to use the gas volume formula. It is important to pay attention to the information on the molar volume of the gases, that is, any gas that occupies 1 mol will be represented by the value 22.4l.

To calculate the volume of a gas, we use the formula:

  • PV = nRT
  • P = Pressure
  • V = Volume
  • n = number of moles of gas
  • T = Temperature
  • R = Universal gas constant

Substituting for the values provided by the question, we can calculate as follows:

Volume Reacting x Solution Molarity x Mole Ratio of reaction x Molar volume of gas = Volume produced

So:

10.0l solution x 5.00 mol [tex]K_{2}MNO_{4}[/tex] ÷ 1l solution x 1 mol [tex]H_{2}[/tex] ÷ 2 mol [tex]K_{2}MNO_{4}[/tex] x 22.4l gas ÷ 1 mol gas = 560l [tex]H_{2}[/tex]

Find out more about gas volume here:

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