The lengths of the legs of the right triangle are 7 and 24. That is,
7, 24
From the question, we are to calculate the length of each leg of the right triangle
From the given information,
Hypotenuse of the right triangle = 25 feet
The length of one leg of the triangle is 10 feet more than twice the other leg
Let the length of the other leg be x
Then,
Length of one of the legs = 10 + 2x
Using the Pythagorean theorem, we can write that
(10 + 2x)² + x² = 25²
(10 + 2x)(10 + 2x) + x² = 625
100 + 20x + 20x + 4x² + x² = 625
100 + 40x + 5x² = 625
5x² + 40x = 625 - 100
5x² + 40x = 525
Divide through by 5
x² + 8x = 105
x² + 8x - 105 = 0
Solve quadratically
x² +15x -7x - 105 = 0
x(x + 15) -7(x + 15) = 0
(x -7)(x + 15) = 0
x - 7 = 0 OR x + 15 = 0
x = 7 OR x = -15
Since x cannot be negative, the value of x is 7
Recall,
The length of one of the legs = 10 + 2x
= 10 + 2(7)
= 10 + 14
= 24
Hence, the lengths of the legs of the right triangle are 7 and 24. That is, 7, 24
Learn more on Calculating the legs of a right triangle here: https://brainly.com/question/917409
#SPJ1