in her last computer game Lucy scored three times 10 to the power of seven points the first time she tried the game she scored six times 10 to the power of three points how many times as many points is Lucy's last score as her first score

Lucy scored 5000 times her first score.
To find how many times as many points is Lucy's last score compared to the first score, we must see how much is the ratio created when dividing the final score by the first score.
[tex]\frac{3*10^7}{6x10^3}[/tex]
This is the property: [tex]\frac{a^m}{a^n}=a^{m-n}[/tex]
Hence, [tex]\frac{3}{6}*\frac{10^7}{10^3} =\frac{3}{6}*10^4[/tex]
[tex]\frac{3/3}{6/3}*10^4\\ \\\frac{1}{2} *10^4\\\\ 0.5*10^4[/tex]
[tex]=5000[/tex]
Lucy scored 5000 times her first score.
Answer:
5 × 10³ = 5000
Step-by-step explanation:
Standard Form (also called "Scientific notation") is written in the form of
[tex]a \times 10^n[/tex] , where [tex]1\leq a < 10[/tex] and n is any positive or negative whole number.
Given:
To calculate how many times as many points is Lucy's last score as her first score, divide her latest score by her first score:
[tex]\implies \dfrac{3 \times 10^7}{6 \times 10^3}[/tex]
[tex]\implies \dfrac{3}{6} \times \dfrac{10^7}{10^3}[/tex]
[tex]\implies 0.5 \times \dfrac{10^7}{10^3}[/tex]
[tex]\textsf{Apply the quotient rule of exponents} \quad \dfrac{a^b}{a^c}=a^{b-c}:[/tex]
[tex]\implies 0.5 \times 10^{7-3}[/tex]
[tex]\implies 0.5 \times 10^{4}[/tex]
In standard form:
[tex]\implies 5 \times 10^{3}[/tex]
Therefore:
[tex]\begin{aligned} \implies 5 \times 10^{3} & =5 \times 10 \times 10 \times 10\\ & =5 \times 1000 \\& =5000 \end{aligned}[/tex]
Learn more about exponent rules here:
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