Be sure to answer all parts.
A pool is 40.4 m long and 27.5 m wide. If the average depth of water is 3.00 ft, what is the
mass (in kg) of water in the pool? Enter your answer in scientific notation.
The density of water is 1.0 g/mL.

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Lanuel

The mass (in kg) of water in the pool is equal to 10.159 × 10⁵ kg.

How to calculate the mass of water in the pool?

First of all, we would convert the value of the average depth of water in feet to meter by using an appropriate conversion factor:

1 foot = 0.3048 meter

3.00 feet = X meter

Cross-multiplying, we have:

X = 3.00 × 0.3048

X = 0.9144 meter.

Next, we would determine the volume of the pool by using this formula:

Volume = length × width × depth

Volume = 40.4 × 27.5 × 0.9144

Volume = 1,015.90 m³

To milliliters, we have:

Volume = 10.159 × 10⁸ mL

Mathematically, the mass of an object can be calculated by using this formula:

Mass = Density × Volume

Mass = 1.0 × 10.159 × 10⁸

Mass = 10.159 × 10⁸ g

To kg, we have:

1 kg = 1000 g.

Mass = 10.159 × 10⁸ 10³

Mass = 10.159 × 10⁽⁸ ⁻ ³⁾

Mass = 10.159 × 10⁵ kg.

Read more on density here: https://brainly.com/question/28353916

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