Respuesta :
Critical angle for the total internal reflection icrit, β = 78.28⁰
Critical angle for the total internal reflection crit, α = 17,22⁰
We have the refractive index of core, [tex]n_c_o_r_e[/tex] = 1.46
We have the refractive index of clad , [tex]n_c_l_a_d[/tex] = 1.4
Critical angle can be defined as the incidence angle which results in the refraction angle being equal to at that angle of incidence.
For Total Internal Reflection to occur, the incidence angle must be greater than the critical angle.
We know that the critical angle, θ is given by:
sinθ = [tex]\frac{n_c_l_a_d}{n_c_o_r_e}[/tex]
sinθ = [tex]\frac{1.4}{1.46}[/tex]
sinθ = 0.959 = sin⁻¹(0.979) = 78.28⁰
β = θ = 78.28⁰
Now, for α:
[tex]\frac{sin(90-\alpha )}{sin\alpha } = \frac{1}{n_c_o_r_e}[/tex]
sinα = sin(90⁰-78.28⁰) × 1.46
sinα = sin(11.72⁰) × 1.46
α = sin⁻¹(0.296)
α = 17,22⁰
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Critical angle for total internal reflection icrit β = 78.28⁰
Critical angle for total internal reflection crit, α = 17.22⁰
- The critical angle can be defined as the angle of incidence at which the angles of refraction are equal to angle of incidence.
- The angle of incidence must be greater than the critical angle for total internal reflection to occur.
The refractive index of the core is ncore = 1.46.
The refractive index of clad is nclad = 1.4.
We know that the critical angle, θ is given by:
sinθ = nclad/ ncore
sinθ = 1.4/1.46
sinθ = 0.959
sin⁻¹(0.979) = 78.28⁰
β = θ = 78.28⁰
Now, for α:
sin(90- α) / sin α = 1 / ncore
sinα = sin(90⁰-78.28⁰) × 1.46
sinα = sin(11.72⁰) × 1.46
α = sin⁻¹(0.296)
α = 17.22⁰
Critical angle for icrit β = 78.28⁰
Critical angle for crit α = 17.22⁰
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