The mass of the rider 1 is equal to 4 grams.
In accordance with the statement, we know the mass of the entire system formed by three riders, of which the mass of two riders are known. The mass of the third rider can be calculated from the previous information:
m = m₁ + m₂ + m₃
Where:
m₁ = m - m₂ - m₃
m₁ = 694 g - 600 g - 90 g
m₁ = 4 g
The mass of the rider 1 is equal to 4 grams.
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