Respuesta :

Answer:

18

Step-by-step explanation:

Distance Formula: [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Plug the points into the formula and solve

[tex]=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\=\sqrt{(28-28)^2+(6+12)^2}\\=\sqrt{(0)^2+(18)^2}\\=\sqrt{324}\\=18[/tex]

The distance between the two given points (28,-12) and (28,6) is 18.

What is the distance between the two given points?

Formula for the distance between two points is expressed as;

D = √( ( x₂ - x₁)² + ( y₂ - y₁ )²

Given the data in the question;

For point (28,-12)

  • x₁ = 28
  • y₁ = -12

For point (28,6)

  • x₂ = 28
  • y₂ = 6

We plug in the values into the formula above.

D = √( ( 28 - 28)² + ( 6 - (-12) )²

D = √( ( 0 )² + ( 6 + 12 )²

D = √( 0 + ( 18 )² )

D = √( 0 + 324 )

D = √( 324 )

D = 18

Therefore, the distance between the two given points (28,-12) and (28,6) is 18.

Learn more about distance formula here: https://brainly.com/question/28280765

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