a. The one-variable equation is W + 115 = 200
b. The width of the hockey rink is 85 ft
a. How to find the one-variable equation for the width of the hockey rink?
Let
- L = length of hockey rink and
- W = width of hockey rink
Given that the length of a hockey rink is 115 feet greater than the width, we have that
L = W + 115
Also, the length of the hockey rink is 200 feet.So, L = 200 ft
Since L = 200 ft and L = W + 115, equating both expressions, we have
W + 115 = 200
So, the one-variable equation is W + 115 = 200
b. How to find the width of the hockey rink?
Since W + 115 = 200
Solving for W, we have
W + 115 = 200
W =200 - 115
W = 85 ft
So, the width of the hockey rink is 85 ft
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