Please help me!

.Use the graphic at the bottom. Developing a Roll of Film The Photo Lab $3.20 per roll plus 8c per print Specialty Photos $2.60 per roll plus 10¢ per print 24 EXP (a)Write equations that represent the cost of developing a roll of film at each lab. (b)Under what conditions is the cost to develop a roll of film the same for either store?​

Please help meUse the graphic at the bottom Developing a Roll of Film The Photo Lab 320 per roll plus 8c per print Specialty Photos 260 per roll plus 10 per pri class=

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Answer:

Photo Lab: [tex]y[/tex] =3.20x +8

Specialty Photos: [tex]y[/tex] =2.60x + 10

Step-by-step explanation:

At the Photo Lab, the cost is $3.20 per roll plus 8 per print.

Therefore, the cost of developing a roll of film is:

[tex]y[/tex] =3.20x +8

At Specialty Photos the cost is $2.60 per roll plus 10 per print.

Therefore, the cost of developing a roll of film is:

[tex]y[/tex] =2.60x + 10

Answer:

(a)

Photo Lab Cost = 3.20 + 0.08X
Specialty Photos Cost  = 2.60 + 0.10X

(b) 30 prints is the number of prints needed for both costs to be the same

Step-by-step explanation:

Let X be the number of prints processed.  Noting that 8 cents is $0.08 and 10 cents is $0.10,

  • For Photo Lab, the equation for cost will be 3.20 + 0.08X
  • For Specialty Photos, the cost will be 2.60 + 0.10X

In order for both cost to be the same set both cost equations equal(break-even point)

2.60 + 0.10X = 3.20 + 0.08X


0.10X -0.08X = 3.20 -2.60

0.02X = 0.60

or

X = 0.60/0.02 = 30 prints

At prints developing photos at both shops will be the same and can be found by substituting for X in either equation

2.60 + 0.1(30) = 2.60 +  = $5.60

Note

To get 30 prints you need at least 2 rolls since there are only 24 prints. per roll The second roll needs only 6 prints developed and you cannot develop 6/24th of a roll but the whole roll.  However, I read the question as the number of prints from each shop to break even in cost.