The relative rates of this reaction in vessels (1) -(4) where each vessel has the same volume is: "2:1:4:2" (Option C)
The rate of reaction at any given point in time is referred to as the relative rate. For example, at 20 seconds, the relative rate of a reaction is 1/20 or 0.05 s -1, whereas the average rate of reaction for the first 20 seconds is the change in mass divided by the change in time.
It is to be noted that the Rate is given as:
Rate = K (A)(B); while Mole = Number of molecules/Avogadro's number
n = N/Nₐ
Thus, concentration = Mole/Volume = N/(VNₐ)
Hence
A = [N(A)]/[VNₐ]
B = [N(B)/ VNₐ]
Rate = K[A][B]
= k x [N(A)/VNₐ] x [N(B)/VNₐ]
= k'x N(A) x N(B)
Thus, the relative rates of this reaction :
Rate 1: Rate 2: Rate 3: Rate 4 = K'18: k'9: k'36: K'18 =2:1:4:2
Hence, the correct answer is: 2:1:4:2" (Option C)
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Full Question:
What are the relative rates of this reaction in vessels (1) -(4)? Each vessel has the same volume.
a. 1:1:1:1
b. 1:2:2:3
c. 2:1:4:2
d. 4:3:2:1
