Respuesta :

the probability that a randomly selected day from 2013 will have a group trades total within 85,000 of the mean is  0.1328

How to solve for the probability

Mean (u) = 3421439

How to solve for the probability

Standard deviation = 508638.08

We know that:

z = x-u/sd

Now,

P(u - 85000 <= x <= u + 85000)

u = 3421439

We have to put thus in the formula above

= P(3421439 - 85000 and

3421439 + 85000)

= P(3336439,  3506439)

= (3336439 - 3421439) / 508638.08

,3506439-3421439) / 508638.08)

= prob(-0.1671 and 0.1671

under the z table this is

= 0.5664 - 0.4336

= 0.1328

Read more on probability here: https://brainly.com/question/24756209

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