could use help on this thank you in advance!!

1) cos θ = -(√34)/6
2) tan θ = -2/√34
3) sec θ = -6/√34
4) csc θ = 3
5) cot θ = (√34)/2
All the trigonometric functions are positive in Quadrant I.
Sine and cosecant are positive in Quadrant II.
Tangent and cotangent are positive in Quadrant II.
Cosine and secant are positive in Quadrant IV.
We are given that;
sinθ = 2/6
Using trigonometric ratio of sin θ = opp/hyp, means that;
cos θ = (√34)/6
tan θ = 2/√34
Thus, using the quadrants signs as earlier defined for Quadrant II, we have that;
1) cos θ = -(√34)/6
2) tan θ = -2/√34
3) sec θ = 1/cos θ = -1/(√34)/6 = -6/√34
4) csc θ = 1/sin θ = 1/(2/6) = 6/2 = 3
5) cot θ = 1/tan θ = -1/(2/√34) = -(√34)/2
Read more about Trigonometric ratios at; https://brainly.com/question/13276558
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