The percent ionization of the base if the initial concentration of base b in solution is 0.18 m. if the ph of the solution at equilibrium is 13.190 is 86.1%.
It should be noted that pH simply means the potential of hydrogen. It is the scale that's used to specify the acidity as well as the alkalinity of aqueous solution.
In a chemical reaction, chemical equilibrium is the state at which both the reactants and products are present in concentrations that have no further tendency to change with time, so that there is no observable change in the properties of the system
It should be noted that from the question, the PoH will be:
= 14 - 13.190
= 0.810
We'll find the log 10 of the number which will be ,0.155.
Therefore, the percent ionization of the base will be:
= 0.155/0.180 × 100
= 86.1%
Therefore the percent ionization of the base if the initial concentration of base b in solution is 0.18 m. if the ph of the solution at equilibrium is 13.190 is 86.1%.
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