Complete neutralization is defined as when a strong acid is mixed with a strong base.
In case of strong acid you can take Hydrochloric Acid (HCL) and in case of strong base you can take the example of Sodium Hydroxide (NaOH). When the mixture dissolved in water (H2O) they(HCL, NaOH) completely disassociates.
Diprotic acid donate two proton per molecule. Ex- Sulphuric Acid (H2SO4)
Now according to question,
AH2+2NaOH → Na2A + 2H2O
n(AH2)=0.1715 L *0.75 mol NaOH* 1 mol AH2/ 2 mol NaOH = 0.0643125 mol
m = 6.50g / 0.0643125 mol
= 101.068999 g/ mol
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