The approximate thickness of the aluminum foil in millimeters is 0.0193 mm when aluminum in a package containing 76 [tex]ft^{2}[/tex] of kitchen foil weighs approximately 13 ounces. aluminum has a density of 2.70 g/[tex]cm^{3}[/tex]
Calculation ,
The thickness of aluminium foil is calculated by following steps ,
First: 13 oz × 28.4 g/oz = 369.2 g
Second: 369.2 g × 1[tex]cm^{3}[/tex]/2.7g = 136.74 [tex]cm^{3}[/tex]
Third: 76 [tex]ft^{2}[/tex] × 12 in/ft × 12 in/ft × 2.54 cm/in × 2.54 cm/in = 70606.3104 [tex]cm^{2}[/tex]
Fourth: 70606.3104 [tex]cm^{2}[/tex] × Thickness = 136.74 [tex]cm^{3}[/tex]
Solve for Thickness: 136.74 [tex]cm^{3}[/tex]/ 70606.3104 [tex]cm^{2}[/tex] = 0.00193 cm
Last: 0.00193 cm × 10 mm/1 cm = 0.0193 mm
Notice how I have to multiply [tex]ft^{2}[/tex] twice by the conversion factor, because [tex]ft^{2}[/tex] is just ft x ft, and I have to cancel each one. Same goes for [tex]cm^{2}[/tex] .
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