Based on the fact that 45% of the doctors are surgeons, the probability that the sample proportion of surgeons will be less than 39% is 0.9950.
First, find the standard deviation:
= √(0.45 x 0.55 / 457)
= 0.0233
Then find the p value:
= P > ((0.39 - 0.45)/0.0233)
= P (z > -2.58)
= 1 - P (z < -2.58)
We can then use a spreadsheet to solve for the probability:
= 1 - NORM.S.DIST(-2.58, 1)
= 0.9950
Find out more on the p value at https://brainly.com/question/4621112
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