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It will require 619s for a constant current of 0.780amp to deposit 0.341 g of tl(iii) as tl(s) on a cathode.
What is Cathode?
The electrode from which a regular current exits a polarised electrical device is known as the cathode. The acronym CCD, short for Cathode Current Departs, can help you remember this definition. The movement of positive charges is referred to as a conventional current. Electrons move in the opposite direction to the usual current flow because they have a negative electrical charge. As a result, the mnemonic cathode current departs also denotes that electrons travel from the external circuit to the device's cathode. Anode refers to the electrode through which regular current travels the other way, into the device.
According to the question:
Tl3+ + 3e- → Tl(s)
96500 coulombs can deposit 1 equivalent Tl
The atomic mass of Tl = 204.3833 u
Therefore, 96500 coulomb can deposit (204.3833)/3 = 68.1277 g Tl
0.341 g of Tl can be deposited by (96500 coulomb x 0.341)/68.1277 = 483.0120 coulomb
Therefore,
483.0120 coulomb = 0.780 A x Time(s)
Time(s) = (483.0120)/0.780 = 619 s
Calculate the time required for a constant current of 0.780 A to deposit 0.341 g of Tl(III) as Tl(s) on a cathode = 619 s
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