Respuesta :
According to the given statement:
the rate of energy radiation from a blackbody per unit area at 237K = 315 W/m²
the rate of energy radiation from a blackbody per unit area at 2370K = 315 x 10⁴ W/m²
What exactly is blackbody radiation used for?
Testing and measuring, illumination, heating, security, as well as thermal imaging are some of the applications for blackbodies. Because the Planck Law of Radiation can be applied to compute the intensity of energy at any wavelength as well as temperature.
According to the given data:
(a). When T=273 K
The following expression gives the rate is energy radiation every unit area of a blackbody:
E = σεT⁴
Substitute the necessary values in above expression
E = (5.6 x 10⁻⁸ w/m²K⁴) (1) (273K)⁴
= 315 W/m²
(b). When T=2730 K
The following expression gives the rate is energy radiation every unit area of a blackbody:
E = σεT⁴
Substitute the necessary values in above expression
(5.67 x 10⁻⁸ w/m²K⁴) (1) (2730K)⁴
= 315 x 10⁴ W/m²
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