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Enter your answer in the provided box. what is the emf of a cell consisting of a pb2 / pb half-cell and a pt / h / h2 half-cell if [pb2 ] = 0.57 m, [h ] = 0.090 m and ph2 = 1.0 atm ? v

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okpalawalter8

The emf of a cell is mathematically given as

[tex]E_{cell}[/tex]  = 0.0532 v

What is the emf of a cell?

Generally, the equation for emf  is mathematically given as

[tex]Pb/Pb^2^+ //\ H / H_2[/tex]

where,

Pb is lead

H is hydrogen

[tex]Pb^{2+}[/tex] / Pb has a standard reduction potential of -0.126 volts, while

[tex]H_2[/tex] / [tex]H_2[/tex] has a standard reduction potential of 0.0 volts.

[tex]E_{cell }= E^0_{cell} - 0.059/n log 1/[/tex][tex][Pb^2^+] x [H^+]^2[/tex]

[tex]E_{cell}[/tex] = 0.126 -  0.059/2 log 1  /  [0.57] x [0.09]^2

[tex]E_{cell}[/tex]  = 0.0532 v

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