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If three numbers x, y, and z are chosen at random from the interval [0, 27], what is the probability that the three numbers are a solution to the equation x y z = 27?

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onyebuchinnaji

The probability that three numbers are the solution of the equation is 1/27.

Total outcome of the number set

The total possible outcome or numbers in the is 27.

0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27.

total = 27

three numbers whose products is 27

xyz = 27

(1)(3)(9) = 27

probability of the numbers whose product is 27 is calculated as follows;

p = possible numbers / total outcome

p = 1/27

Thus, the probability that three numbers are the solution of the equation is 1/27.

Learn more about probability here: https://brainly.com/question/24756209

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