The intersecting points of two curves are
[tex]10 cos[/tex]θ[tex]=\frac{1}{2}[/tex]
[tex]= > cos[/tex]θ[tex]=\frac{1}{2}[/tex]
By substituting, therefore the equation becomes,
[tex]= 25 [\frac{\sqrt{3} }{2}+\frac{2}{3}-\frac{25}{3}\\ =\frac{25\sqrt{3} }{2} + \frac{25(\frac{22}{7}) }{3}[/tex]
The region enclosed by the function we're dealing with, vertical lines denoting the function's boundaries, and the -axis is known as the area under the curve. The continuous function's area under the curve, as depicted in the graph above. The function's vertical boundaries are represented by the interval. The region enclosed by the function we're dealing with, vertical lines denoting the function's boundaries, and the -axis is known as the area under the curve.
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