Given: f(x) = x + 2 and h(x) =
Evaluate the following function at x=2.

[tex]\frac{(h(2) )^2}{f(2)}=\frac{1}{4} .[/tex]
To evaluate the function at x= 2, substitute the value of x by 2 in the expression of the function and calculate. Do it like this:
[tex]\frac{(\frac{1}{x-1} )^2}{x+2}[/tex]
[tex]\frac{(\frac{1}{(2)-1} )^2}{(2)+2}[/tex]
[tex]\frac{(\frac{1}{(2)-1} )^2}{4}[/tex]
[tex]\frac{(\frac{1}{1} )^2}{4}\\ \\\frac{(1 )^2}{4}\\ \\\frac{1}{4} \\[/tex]
[tex]\frac{(h(2) )^2}{f(2)}=\frac{1}{4} .[/tex]