The thickness of the barrier that will stop a car travelling at 76.86 km/h is 0.76 m.
The thickness of the barriers can be calculated using a kinematic equation as shown below;
v² = u² + 2ad
where;
The given final velocity of the car;
v = 76.86 km/h = 21.35 m/s
Thickness of the barrier that will stop a car travelling at 76.86 km/h is calculated as follows;
d = v²/2a
d = (21.35²) / (2 x 300)
d = 0.76 m
Thus, the thickness of the barrier that will stop a car travelling at 76.86 km/h is 0.76 m.
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