Answer:
[tex] \large \bf \implies{25 {h}^{ - 2}} \\ [/tex]
Step-by-step explanation:
[tex] \bf \longrightarrow \bigg( \frac{h}{5} \bigg)^{ - 2} \\ \\ \bf \longrightarrow \bigg(\frac{5}{h} \bigg)^{2} \\ \\ \bf \longrightarrow \frac{ {5}^{2} }{ {h}^{2} } \\ \\ \bf \longrightarrow \frac{25}{ {h}^{2} } \\ \\ \bf \longrightarrow25 {h}^{ - 2} [/tex]
Note :- We have using the negative exponent rule :
[tex] \large \mapsto \bf \boxed{ \bf \red{{a}^{ - n} = \frac{1}{ {a}^{n} } }}[/tex]
