Respuesta :

mastercookie55

Answer:

[tex]y=\frac{2}{5}x-3[/tex]

or

[tex]y+3=\frac{2}{5} (x-0)[/tex]

Step-by-step explanation:

Finding the Equation of a Line Given Two Points:

  • In order to find the equation of a line, we must identify point (x,y) and slope (m).
  • Slope formula:  [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
  • Point-slope formula: [tex]y-y_1=m(x-x_1)[/tex]
  • Slope-intercept formula: [tex]y=mx+b[/tex]

We are given two points on Line A: (0,-3) and (5,-1). We can assign each integer to a variable in the slope formula (see above):

[tex]x_1=0[/tex]

[tex]y_1=-3[/tex]

[tex]x_2=5[/tex]

[tex]y_2=-1[/tex]

As we have identified point, we can now work to identify slope by substituting our points into the slope formula:

[tex]m=\frac{-1-(-3)}{5-0}=\frac{2}{5}[/tex]

Now that we have identified both point and slope for Line A, we can format these values in point-slope form. Substitute values into the formula:

[tex]y-(-3)=\frac{2}{5} (x-0)=y+3=\frac{2}{5}x[/tex]

Solve for [tex]y[/tex] to achieve an answer in slope-intercept form ([tex]y=mx+b)[/tex]:

[tex]y=\frac{2}{5} x-3[/tex]

Otras preguntas