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Eduard22sly

The mass (in grams) of xenon in 3.541 g of the compound xenon tetrafluoride is 2.243 grams

Composition of xenon tetrafluoride, XeF₄

1 mole of XeF₄ contains the following:

  • 1 mole of XeF₄ = 131.3 + (4 × 19) = 131.3 + 76 = 207.3 g
  • 1 mole of XeF₄ contains 131.3 g of Xe
  • 1 mole of XeF₄ contains 76 g of F

How to determine the mass of Xe in 3.541 g of XeF₄

The mass of Xe in 3.541 g XeF₄ can be obtained as illustrated below:

207.3 g of XeF₄ contains 131.3 g of Xe.

Therefore,

3.541 g of XeF₄ will contain = (3.541 g × 131.3 g) / 207.3 g = 2.243 g of Xe

Thus, 2.243 g of Xe is present in 3.541 g of xenon tetrafluoride, XeF₄

Learn more about mass composition:

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