The useful output power of the motor is 2 Watts
Power is the rate at which work is done. It is measured in watt.
Given that an electric motor has a power input of 3.0 watts when lifting a weight. The weight gains 10 Joules of potential energy in 5.0 seconds
The parameters to be considers are
The useful output power P of the motor = E/t
P = 10/5
P = 2 Watts
Therefore, the useful output power of the motor is 2 Watts
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