[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
By Pythagoras theorem :
[tex]\qquad \sf \dashrightarrow \: hypotenuse = \sqrt{(perpendicular) {}^{2} + (base) {}^{2} } [/tex]
[tex]\qquad \sf \dashrightarrow \: h= \sqrt{15 {}^{2} + {8}^{2} } [/tex]
[tex]\qquad \sf \dashrightarrow \: h = \sqrt{225 + 64} [/tex]
[tex]\qquad \sf \dashrightarrow \: = \sqrt{289} [/tex]
[tex]\qquad \sf \dashrightarrow \: h = 17 \: \: units[/tex]
Now, we know ~
[tex]\qquad \sf \dashrightarrow \: \sin(A) = \dfrac{opposite \: \: side}{hypotenuse} [/tex]
[tex]\qquad \sf \dashrightarrow \: \sin(A) = \dfrac{8}{17} [/tex]