But the query isn't complete. The hammer traveled 4.26 meters horizontal distance
we have following the given data
Hammer speed is 4 m/s.
30° is the angle the roof makes with the horizontal.
Roof's minimum height above ground is equal to 10 m g/10 m/s2.
Find the hammer's horizontal distance traveled.
Considering the vertical y-direction to establish the Time (t)
s = ut + 1/2at²
-10 = -4×sin30×t + 1/2×10t²
10 = 2t + 5t²
5t² + 2t - 10 = 0 (i)
Resolve equation (i)
t = 1.228 sec
This formula is used to compute the horizontal distance.
4 (cos 30°) t = 4×cos 30×1.228 = 4.26 m
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