The games that can be played for about places to cost the same is 3 games.
Let the number of games be represented by b.
The event charges $3 for bowling shoe rental and $10 per bowling. This can be represented as:
= 3 + 10b
MaxBowl charges $6 to run bowling shoes and $9 per bowling game. This will be:
= 6 + 9b
We will equate them together:
3 + 10b = 6 + 9b
Collect like terms
10b - 9b = 6 - 3
b = 3
Therefore, the games that can be played for about places to cost the same is 3 games.
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