A volume of 293 mL of oxygen gas was collected at a temperature of 10°C and a pressure of 102 kPa. What

volume of oxygen would be collected at STP?

Respuesta :

Volume of oxygen would be collected at STP is 293.3 ml

V1 = 293 mL

V2 = ?

P1 = 102 kPa

P2 = 100 kPa

T1 = 10°C = ( 273 + 10 ) = 283 k

T2 = 273 k

The Combined Gas Law combines Charles Law, Boyle s Law and Gay Lussac s Law. The Combined Gas Law states that a gas pressure x volume x temperature = constant

The combined gas law is an amalgamation of the three previously known laws which are- Boyle's law PV = K, Charles law V/T = K, and Gay-Lussac's law P/T = K. Therefore, the formula of combined gas law is PV/T = K, Where P = pressure, T = temperature, V = volume, K is constant.

P1V1/T2 = P2V2/T2

102 x 293 / 283 = 100 x V2 / 273

105.6 = 0.36 x V2

105.6/0.36 = 293.3

V2 = 293.3 ml

Hence, volume of oxygen would be collected at STP is 293.3 ml

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