Final temperature of the two pieces of metal is 32.25°C
Temprature is the degree of hotness or coldness of the object
Here given data is
Mass of iron = 150 g
Mass of copper = 275 g
Specific heat of iron = 25.09 J/mol°C
Specific heat of copper = 25.46J/mol°C
Temprature in iron = 47°C = initial temprature = T₁
Temprature in copper = 20°C = initial temprature = T₁'
So here we have to find final temprature of two pieces of metal =?
So, the formula is Q =mcΔT
Q = (150 g - 275 g) × (25.09 J/mol°C - 25.46J/mol°C) × ( 47°C-20°C )
Q = 125×0.37×27
Q = 243 J
243 J/125×0.37 = 5.25°C = change in temprature
Initial temprature = 27°C
Final temprature = ?
ΔT = T₂ - T₁
27°C = T₂ - 5.25°C
T₂ = 27°C + 5.25°C
T₂ = 32.25°C
Final temperature of the two pieces of metal is 32.25°C
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