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Write the equation of the line that passes through the points (3,1)(3,1) and (-7,-1)(−7,−1). Put your answer in fully simplified point-slope form, unless it is a vertical or horizontal line.

Respuesta :

semsee45

Answer:

[tex]\textsf{Point-slope form}: \quad y-1=\dfrac{1}{5}(x-3)[/tex]

Step-by-step explanation:

Define the given points:

  • (x₁, y₁) = (3, 1)
  • (x₂, y₂) = (-7, -1)

Substitute the defined points into the slope formula to find the slope of the line:

[tex]\implies \textsf{Slope $(m)$}=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{-1-1}{-7-3}-\dfrac{-2}{-10}=\dfrac{1}{5}[/tex]

Substitute the found slope and one of the points into the point-slope formula:

[tex]\implies y-y_1=m(x-x_1)[/tex]

[tex]\implies y-1=\dfrac{1}{5}(x-3)[/tex]

Simplify to slope-intercept form, if necessary:

[tex]\implies y-1=\dfrac{1}{5}x-\dfrac{3}{5}[/tex]

[tex]\implies y=\dfrac{1}{5}x+\dfrac{2}{5}[/tex]

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