a bank loaned out $23,000, part of it at the rate of 11% annual interest, and the rest at 12% annual interest. the total interest earned for both loans was $2,595.00. how much was loaned at each rate

Respuesta :

The portion of the loan  11% is 23000(0.4954) = $11,394.2

And the portion of the loan 15% is 23000(0.3045) = $7015

Let x be the amount loaned at 11% annual interest so that 23000-x represents the amount loaned at 12% annual interest.

The total interest earned for both loans was $2,595.00 so we can write:

23000(P) = $2,595

P = 0.09 or 9.00 %

This number is a weighed average of the 4% yield and the 15% yield so the next equation to solve is

9.00 = 11 (1 – X) + 12X

Where X is the proportion of the loan given at the indicated interest. So

10.55 = 11 – 11X + 12X

5.45 = 11X

X = 0.4954

1-X = 0.3045

So the portion of the loan 11% is 23000(0.4954) = $11,394.2

And the portion of the loan  15% is 23000(0.3045) = $7015

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