Respuesta :
By using the balanced reaction equation of ethane combustion, we can calculate that 12.8 L of carbon dioxide will be produced.
To calculate the answer to this, we need to write the balanced reaction equation:
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
Based on this, we can see that 2 moles of ethane produce 4 moles of carbon dioxide. Now, we need to calculate the number of moles (n) of ethane using its mass (m = 8.00 g) and its molar mass (M = 30.07 g/mol):
n = m/M
n = 8.00 g / 30.07 g/mol
n = 0.266 mol
Based on this, we can conclude that 2 * 0.266 mol = 0.532 mol of carbon dioxide was produced. Assuming that carbon dioxide acts as an ideal gas, we can use the ideal gas equation to calculate its volume:
PV = nRT ⇒ V = nRT/P
V - the volume of the gas
n - number of moles of gas (0.523 mol)
R - universal gas constant (0.08206 L*atm/K*mol)
T - temperature in Kelvins (25 °C = 298.15 K)
P - pressure (1.00 atm)
Now we plug all the known values into the equation:
V = 0.523 mol * 0.08206 L*atm/K*mol * 298.15 K / 1.00 atm
V = 12.8 L
You can learn more about balanced reaction equations here:
brainly.com/question/22064431
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