Respuesta :
The main assumption to make is that the density of 5% vinegar is equal to the density of water. Then, for the purposes of the calculation, it is easiest to assume a certain volume of 5% vinegar is used. With these assumptions, we can calculate that the molarity of the solution is 0.83 M.
To calculate the molarity (c) of the solution, we need the number of moles (n) of solute and the volume (V) of the solution:
c = n/V
If we assume that we have 100 mL of 5% vinegar and that its density (d = 1.00 g/mL) is equal to the density of water, we can calculate the mass of the solution (m) using its density and volume (V = 100 mL = 0.100 L):
d = m/V ⇒ m = d*V
m = 1.00 g/mL * 100 mL
m = 100 g
Now we can use the mass and mass percentage (%m = 5% = 0.05) to calculate the mass of acetic acid (AcOH) present:
m(AcOH) = %m * m(solution)
m(AcOH) = 0.05 * 100 g
m(AcOH) = 5 g
Using the mass of AcOH we can calculate the number of moles (n) present by using the molar mass of AcOH (M = 60 g/mol):
n = m/M
n = 5 g / 60 g/mol
n = 0.083 mol
Finally, we calculate the molarity:
c = 0.083 mol / 0.1 L
c = 0.83 M
You can learn more about molarity here:
brainly.com/question/16727614
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