If a and b are two events defined on the same sample space, given that p(a) = 0.28 and p(aub) = 0.51, find the p(b) such that a and b are mutually exclusive

Respuesta :

P(B) such that a and b are mutually exclusive is 0.23

A group of potential results from a specific experiment is an event. Events that do not take place at the same time are said to be mutually exclusive. For instance, if a coin is tossed, the outcome will either be head or tail; we cannot obtain both outcomes. Since they do not occur at the same time, such occurrences are also known as disjunct events.

Given: P(A) =0.28

P(AUB) = 0.51

We know,

P(AUB) = P(A) + P(B) - P(A∩B)

Since A and B are mutually exclusive events, they cannot happen together.

So, P(A∩B) = 0

Then,

P(AUB) = P(A) + P(B)

0.51 = 0.28+ P(B)

P(B) = 0.51 - 0.28 = 0.23.

Hence, P(B) = 0.23

To read more about mutually exclusive events, visit https://brainly.com/question/28565577

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