Given:
Number of boys=10
Number of girls=12
Out of 22 members, 4 members is need to be selected.
To find probability to form a committee consisting of 2 boys and 2 girls:
So, we get
[tex]\begin{gathered} \frac{^{10}C_2\times^{12}C_2}{^{22}C_4}=\frac{\frac{10\times9}{2\times1}\times\frac{12\times11}{2\times1}}{\frac{22\times21\times20\times19}{4\times3\times2\times1}} \\ =\frac{5\times9\times6\times11}{11\times7\times5\times19} \\ =\frac{9\times6}{7\times19} \\ =\frac{54}{133} \\ =0.4060 \end{gathered}[/tex]Hence, the correct option is B.
