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A salt solution has a molarity of 1.5 M. How many mole of this salt are present in 2.0 L of this solution.A. 1.5 molesB. 2.0 molesC. 3.0 moles D. 0.75 mole

Respuesta :

Answer:

[tex]C\text{ : 3.0 moles}[/tex]

Explanation:

Here, we want to get the number of moles present in the solution

Mathematically:

[tex]Number\text{ of moles = molarity }\times\text{ volume in L}[/tex]

From the question:

We have the molarity as 1.5 M

We have the volume as 2.0 L

Thus, we have the number of moles as:

[tex]1.5\text{ }\times\text{ 2 = 3.0 moles}[/tex]

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