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Select the two values of x that are roots of this equation.3x² + 1 = 5xA. x =5+√13x = 5+√136☐ B. x =5-√136□ C. x=-1-√59X6D. X =-1+√596

Select the two values of x that are roots of this equation3x 1 5xA x 513x 5136 B x 5136 C x159X6D X 1596 class=

Respuesta :

3x^2 + 1 = 5x

3x^2 - 5x + 1 = 0

quadratic formula

[tex]x=-\frac{b\pm\sqrt{b^2-4ac}}{2a}[/tex]

where ax^2 + bx + c = 0

so

[tex]x=\frac{5\pm\sqrt{-5^2-4(3)(1)}}{2(3)}[/tex][tex]x=\frac{5\pm\sqrt{25-12}}{6}[/tex]

You can see that the 25 - 12 = 13 so the answers are A and B

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