In the right triangle, there is a relation between the 2 legs of the right angle and the hypotenuse (the opposite side to the right angle)
[tex](hypotenuse)^2=(leg1)^2+(leg2)^2[/tex]From the given figure
∵ leg1 = 7 ft
∵ leg2 = h ft
∵ hypotenuse = 16 ft
→ Substitute them in the rule above to find h
[tex](16)^2=(7)^2+h^2[/tex]∵ 16^2 = 256 and 7^2 = 49
[tex]\therefore256=49+h^2[/tex]→ Subtract 49 from both sides
[tex]\begin{gathered} 256-49=49-49+h^2 \\ 207=h^2 \end{gathered}[/tex]→ Take square root for both sides to find h
[tex]\begin{gathered} \therefore\sqrt[]{207}=\sqrt[]{h^2} \\ 14.38749=h \end{gathered}[/tex]→ Round it to the nearest tenth
∴ h = 14.4 feet
The answer is B
