In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
∆ABC~∆DEF
triangle 1:
AC = 10
area = 65 in²
triangle 2:
DF = 20
area = ?
Step 02:
We must apply the rules of similar triangles to find the solution. .
[tex]\frac{triangle\text{ 1 AC}}{\text{triangle 2 DF }}=\frac{triangle\text{ 1 area}}{\text{triangle 2 area}}[/tex][tex]\frac{10}{20}=\frac{65in^2}{triangle\text{ 2 area}}[/tex]
triangle 2 area * 10 = 65 in² * 20
triangle 2 area = (65 in² * 20 ) / 10
= 130 in²
The answer is:
The area of the big triangle is 130 in² .
