Given the formula for the perimeter of a rectangle, p=2l+2wwhich answer would you get if you solve for l? pāˆ’2w 2 p/w-2 p/2āˆ’2w pāˆ’2l/2

Given the formula for the perimeter of a rectangle p2l2wwhich answer would you get if you solve for l p2w 2 pw2 p22w p2l2 class=

Respuesta :

If we have:

[tex]p=2w+2l[/tex]

To solve for l we can start by inverting the sides and substracting 2w from both sides so that the term with l becomes alone in the left side:

[tex]\begin{gathered} p=2w+2l \\ 2w+2l=p \\ 2w-2w+2l=p-2w \\ 2l=p-2w \end{gathered}[/tex]

Now, we can divide both sides by 2 so thay the 2 in 2l gets canceled:

[tex]\begin{gathered} 2l=p-2w \\ \frac{2l}{2}=\frac{p-2w}{2} \\ l=\frac{p-2w}{2} \end{gathered}[/tex]

So, the answer we would get is

[tex]\frac{p-2w}{2}[/tex]