Respuesta :
This organic compound has in its structure the next element: C, H, and O
45.27% C
4.43 % H
The rest 100%-45.27%-4.43 = 50.3 % O
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The empirical formula of a chemical compound is the simplest whole-number ratio of atoms present in a compound.
Procedure:
Step 1)
We convert % into grams (g). Let's assume we have a 100g sample. Therefore,
45.27 % C = 45.27 g
4.43 % H = 4.43 g
50.3 % O = 50.3 g
Step 2)
We calculate the number of moles of each element. To do this, we need every atomic mass
For C)
[tex]45.27\text{ g x }\frac{1\text{ mol}}{12.01\text{ g}}=3.767\text{ moles}[/tex]For H)
[tex]4.43\text{ g x }\frac{1\text{ mol}}{1.00\text{ g}}=\text{ 4.43 moles}[/tex]For O)
[tex]50.3\text{ g x }\frac{1\text{ mol}}{16.0\text{ g}}=3.14\text{ moles}[/tex]Step 3)
We divide all moles by the smallest one of them (3.14 moles of O)
For C) 3.767 moles/3.14 moles = 1.19 = 1 (we need integer numbers)
For H) 4.43 moles/3.14 moles = 1.41 = 1
For O) 3.14 moles/3.14moles = 1
The empirical formula is CHO
