We must first check the valence number of the sulfur in the sulfate ion. In this ion, the valence number is +6 and we have 4 bonded oxygens.
[tex]\begin{gathered} S^{+6}\lbrack O^{-2}_4\rbrack^{-8} \\ SO^{-2}_4 \end{gathered}[/tex]
The Lewis structure of the sulfate ion is as follows:
We have six bonding in the molecule. So the answer will be B. six bonding and no lone pairs of electrons.
