Answer:
Explanation:
The slope-intercept form of the equation of a line can be written as;
[tex]y=mx+b[/tex]
where m = slope of the line
b = y-intercept of the line
So if Joanne graphed a linear function with a slope(m) of -4 passing through (0, -2), let's go ahead and determine the y-intercept of the line as shown below;
[tex]\begin{gathered} -2=-4(0)+b \\ -2=b \\ b=-2 \end{gathered}[/tex]
Therefore, the equation of line will be y = -4x - 2 as graphed below;
Given Nick's function as y = -2x - 4, combining both graphs, we'll have the below;
The red line is Joanne's line while the blue line is Nick's line.
We can see from the above graph of both lines that Joanne's line intersects the y-axis above Nick's line's
