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The owner of a recycling company wants to reduce his electrical consumption and costs. The electromagnet used in his operation uses 12 A of current, has 7000 loops and a lifting force of 9800 N. If the lifting force needs to remain the same but the owner would like to reduce the current to only 5 A, how many loops would the electromagnet have?

Respuesta :

Given:

Current, I = 12 A

Loops, B = 7000

Force, F = 9800 N

Let's determine the loops if the force remains the same but the current redudces to 5A.

Apply the formula:

[tex]F=\frac{I\times N}{L}[/tex]

Let's solve for L.

[tex]\begin{gathered} L=\frac{I\times N}{F} \\ \\ L=\frac{12\times7000}{9800} \\ \\ L=8.57\text{ m} \end{gathered}[/tex]

If the current reduces to 5 A, we have:

[tex]\begin{gathered} N=\frac{F\times L}{I} \\ \\ \text{Where I = 5 A} \\ \\ N=\frac{9800\times8.57}{5} \\ \\ N=16800\text{ } \end{gathered}[/tex]

The number of loops the electromagnet would have is 16800 loops.

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