Respuesta :

Length: L

Width: W

The area of a rectangle is:

[tex]A=L\cdot W[/tex]

The perimeter of a rectangle is:

[tex]P=2W+2L[/tex]

Given information:

[tex]\begin{gathered} A=2x^2+3x \\ \\ P=6x+6 \end{gathered}[/tex][tex]\begin{gathered} L\cdot W=2x^2+3x \\ 2W+2L=6x+6 \end{gathered}[/tex]

Solve L in the second equation (Perimeter):

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